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Binomial Distribution — Class 12 Maharashtra HSC Mathematics revision notes

A 4-page visual revision sheet for Binomial Distribution, written for Class 12 Maharashtra HSC Mathematics. Formulas, diagrams and the traps that cost marks, laid out to be read the night before rather than the term before. Free, and it opens inside CapCompass.

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Binomial Distribution in one look

n independent trials, each success or failure with the same chance, and every count from 0 to n has its own term in an expansion

Bernoulli Trials

  • trials are Bernoulli if each has two outcomes (success, failure) with the same success probability
  • success/failure are labels: calling even a success fixes p=1/2, three of six faces are even
  • trials must also be independent, so that fixed success probability genuinely applies unchanged every time
  • notation: p is success probability, q=1-p is failure probability, both constant across n trials

Deciding whether draws are Bernoulli trials

Q. six balls are drawn successively from an urn of 7 red and 9 black balls. Are the draws Bernoulli trials (i) with replacement, (ii) without replacement?

  1. with replacement: the urn resets after every draw, so P(red)=7/16 on all six draws
  2. the probability of success stays fixed across all six draws, satisfying both Bernoulli conditions
  3. without replacement: P(red) is 7/16 first, then 6/15 if red was drawn, or 7/15 if black

Answer: with replacement, the draws ARE Bernoulli trials. Without replacement, they are NOT, since the probability of success changes from draw to draw

From three trials to the general term

  1. the sample space is SSS, SSF, SFS, FSS, SFF, FSF, FFS, FFF, and X counts the successes, so X takes values 0, 1, 2, 3
  2. P(X=0)=P(FFF)=q^3. P(X=3)=P(SSS)=p^3
  3. P(X=1)=P(SFF)+P(FSF)+P(FFS)=3pq^2, since three orderings give exactly one success
  4. P(X=2)=P(SSF)+P(SFS)+P(FSS)=3p^2q, since three orderings give exactly two successes
  5. these four probabilities, q^3, 3q^2p, 3qp^2, p^3, are exactly the four terms of the binomial expansion (q+p)^3
  6. generalising to n trials, x successes and (n-x) failures can occur in ^nC_x distinct orderings, and each ordering has probability p^xq^n-x
  7. **P(x successes in n trials) = ^nC_x p^xq^n-x**, the (x+1)th term of the expansion of (q+p)^n

Binomial Distribution

  • probability function of X, for x=0,1,…,n P(x)= ^nC_x p^xq^n-x
  • notation: X follows a binomial distribution with parameters n and p Xsim B(n,p)
  • the two conditions the trials must satisfy n fixed,quad trials independent

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