Arithmetic Progression — Class 10 Maharashtra SSC Mathematics revision notes
A 4-page visual revision sheet for Arithmetic Progression, written for Class 10 Maharashtra SSC Mathematics. Formulas, diagrams and the traps that cost marks, laid out to be read the night before rather than the term before. Free, and it opens inside CapCompass.
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Arithmetic Progression in one look
a list that grows by the same step every time, and the two formulas that follow from it
A sequence: numbers in a fixed order, each with a position
Test the gaps: every consecutive difference is the same
It is an A.P.: first term and common difference describe it fully
The definition, stated carefully
a sequence is an A.P. when the difference between any term and the one before it is constant
that constant is the common difference d, and d = t_2 - t_1 = t_3 - t_2 and so on
d is found by later term minus earlier term, never the other way round
d may be positive, giving a rising list, negative, giving a falling one, or zero, giving a constant list
checking one pair of terms is not enough. A list is an A.P. only if every consecutive difference agrees
The formulas this chapter is built on
the n-th term, counting from the firstt_n = a + (n-1)d
sum of the first n termsS_n = n/2[2a + (n-1)d]
the same sum when the last term is knownS_n = n/2(a + t_n)
recovering a single term from the sumst_n = S_n - S_n-1
sum of the first n natural numbersS_n = n(n+1)/2
Why the n-th term has n minus 1 in it
the first term has had no step added to it yet, so t_1 = a
the second term has had one step added, t_2 = a + d, and the third has had two
so the term at position n has had (n-1) steps, giving t_n = a + (n-1)d
this is the single most useful sanity check in the chapter: substitute n = 1 and the formula must return a
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