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Quadratic Equations — Class 10 Maharashtra SSC Mathematics revision notes

A 5-page visual revision sheet for Quadratic Equations, written for Class 10 Maharashtra SSC Mathematics. Formulas, diagrams and the traps that cost marks, laid out to be read the night before rather than the term before. Free, and it opens inside CapCompass.

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Quadratic Equations in one look

one unknown, highest power two, and three separate ways to reach the roots

  1. Is it quadratic?: one variable, highest index exactly two
  2. Does it factorise?: split the middle term, fastest route when it works
  3. Otherwise: the formula never fails, so it is the fallback

Standard form, and why it comes first

  • every method below assumes the equation is written as ax^2 + bx + c = 0 with a, b and c real and a ≠ 0
  • collect every term on one side before reading off a, b and c, so 3x^2 = 5x - 2 must become 3x^2 - 5x + 2 = 0
  • a is the coefficient of x^2, b of x, and c is the constant, each carried with its own sign
  • the sign travels with the number: in x^2 - 7x + 12 = 0 the value of b is -7, not 7
  • a value of x that satisfies the equation is called a root of the equation, and a quadratic has two of them

Solving by factorisation

  1. write the equation in standard form, so one side is exactly zero
  2. multiply a by c and look for two numbers whose product is ac and whose sum is b
  3. split the middle term using those two numbers, turning three terms into four
  4. group the four terms in pairs and take out the common factor from each pair
  5. the bracket left over is common, so the expression becomes a product of two factors
  6. set each factor to zero separately, because a product is zero only when a factor is zero

Splitting the middle term in full

Q. Solve 3x^2 - 11x + 6 = 0 by factorisation.

  1. here a = 3, b = -11 and c = 6, so ac = 18
  2. two numbers with product 18 and sum -11 are -9 and -2, both negative because the product is positive and the sum negative
  3. split: 3x^2 - 9x - 2x + 6 = 0
  4. group: 3x(x - 3) - 2(x - 3) = 0
  5. take out the common bracket: (x - 3)(3x - 2) = 0
  6. so x - 3 = 0 or 3x - 2 = 0, giving x = 3 or x = 2/3

Answer: x = 3 and x = 2/3

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